In the given circuit the cells have zero internal resistance. The currents (in Amperes ) Passing through resistance R_{1} and R_{2} respectively, are :

  • Option 1)

    1,2

     

     

  • Option 2)

    2,2

  • Option 3)

    0.5,0

  • Option 4)

    0, 1

Answers (1)
A admin

 

Ohm's Law -

Current flowing through the conductor is directly proportional to the Potential difference accross two ends .

- wherein

unit -   \frac{m^{2}}{volt\cdot sec}

 

V \alpha  I

V=IR

R- Electric Resistance

 

for

R_{1}\: \: \: \: \: \: \Delta V=10V\\\\so\: \: \: I=\frac{\Delta V}{R_{1}}=\frac{10}{20}=0.5A\\\\similarly\: for\: R_{2}\\\\ apply \: \: KVL \: \: for\: \: ABCD \\\\we\: \: get \\\\\\0+10V-I(R_{1})-I_{2}R_{2}=0\\\\10V-0.5\times 20-I_{2}R_{2}=0\\\\\Rightarrow I_{2}=0.\\\\\\\ \: I_{1}=0.5A\\\\current \: through R_{1}=I=0.5A\\\\current\: through R_{2}=I_{2}=0A

 

 


Option 1)

1,2

 

 

Option 2)

2,2

Option 3)

0.5,0

Option 4)

0, 1

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