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  • Give answer! - The metal d-orbitals that are directly facing the ligands in are: - Co-ordination Compounds - JEE Main

The metal d-orbitals that are directly facing the ligands in  K_{3}\left [ Co\left ( CN \right )_{6} \right ]  are:

  • Option 1)

    d_{xz},\: \: d_{yz}\: \: and\: \: d_{z^{2}}

  • Option 2)

    d_{xy},\: \: and\: \: d_{x^{2}}-y^{2}

  • Option 3)

    d_{x^{2}-y^{2}}\: \: and \: \: d_{z^{2}}

  • Option 4)

    d_{xy},\: \: d_{xz}\: \: and\: d_{yz}

Answers (2)

best_answer

 

Strong Field Ligand -

These are the ligands which pair the electron in inner d-orbital and makes required d-orbitals empty/available. 

- wherein

For example: CO, CN etc

 

 

Stability of Complex -

Stability of complex is depends on nature of ligands, size of central atom and stability concept.

- wherein

Stability \alpha Stability Constant

 

 

Crystal field splitting in tetrahedral complexes -

t_{2g} orbitals has more value of energies as compared to e_{g}.

- wherein

As we learn

We have learned in comlex compounds K_{3}\left [ CO\left ( CN \right )_{6} \right ]

CO^{3+}\rightarrow \left [ Ar \right ]_{18}3d^{6}fig

Octahedral geometry ,d^{2}sp^{3} hybridisation

 


Option 1)

d_{xz},\: \: d_{yz}\: \: and\: \: d_{z^{2}}

Option 2)

d_{xy},\: \: and\: \: d_{x^{2}}-y^{2}

Option 3)

d_{x^{2}-y^{2}}\: \: and \: \: d_{z^{2}}

Option 4)

d_{xy},\: \: d_{xz}\: \: and\: d_{yz}

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co in  +3 oxidation state and that too with a strong field ligand forms OCTAHEDRAL complex acc to VBT . therfor electrons of the ligand should enter through Eg instead of T2g . therefore acc to iit professors here , ans should be dxy,dyz,dzx ,.... SBGM

 

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Aditya Sorout

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