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Glucose, when heated with \mathrm{CH_3 OH} in presence of dry HCl gas, gives \mathrm{\alpha-\ and\ \beta- methyl\ glycosides} because it contains :

Option: 1

 An aldehyde group


Option: 2

A  \mathrm{-CH_2OH} group


Option: 3

A ring structure


Option: 4

Five hydroxyl groups


Answers (1)

best_answer

Glucose forms \alpha and \beta glucosides upon reaction with \mathrm{CH_3OH} in the presence of dry \mathrm{HCl} as it has a cyclic structure and it is due to this cyclisation that we obtain the two anomers

Therefore, (3) option is correct.

Posted by

Devendra Khairwa

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