Q

# Help me answer: - Electrostatics - JEE Main-11

A cone of base radius R and height h is  located in a uniform electric field parallel to its base. The electric flux entering the cone is :

• Option 1)

• Option 2)

• Option 3)

• Option 4)

120 Views
N

As we discussed in the concept

Electric field \vec{E} through any area \vec{A} -

$\dpi{100} \phi = \vec{E}\cdot \vec{A}=EA\cos \Theta$

$\dpi{100} S.I\; unit\; -\left ( volt \right )m\; or\; \frac{N-m^{2}}{c}$

- wherein

Area of $\Delta$ facing = $\frac{1}{2}\times h\times 2R$

$\therefore \phi = EhR$

Option 1)

Option 2)

Option 3)

Option 4)

Exams
Articles
Questions