Get Answers to all your Questions

header-bg qa

Two condensers of capacity C and 2C are connected in parallel and these are charged upto V volt. If the battery is removed and dielectric medium of constant K is put between the plates of first condenser, then the potential at each condenser is 

  • Option 1) V/(K+2) 
  • Option 2)  {2+(K/3V)} 
  • Option 3) 2V/(K+2) 
  • Option 4) 3V/(K+2) 
 

Answers (1)

best_answer

As we have learned

Parallel Grouping -

C_{eq}=C_{1}+C_{2}+\cdots

- wherein

 

 

Initially                 Equivalent capacitance of the system  


 Total charge  Q= (3C)V 

 Finally                 Equivalent capacitance of the system  

                                                                C_{eq} = KC+2C

Hence common potential      
                                                V= \frac{Q}{(KC+2C)}= \frac{3CV}{(K+2)C}=\frac{3V}{K+2}

 


Option 1)

\frac{V}{K+2}

Option 2)

2+\frac{K}{3V}

Option 3)

\frac{2V}{K+2}

Option 4)

\frac{3V}{K+2}

Posted by

Himanshu

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE