Two condensers of capacity C and 2C are connected in parallel and these are charged upto V volt. If the battery is removed and dielectric medium of constant K is put between the plates of first condenser, then the potential at each condenser is 

  • Option 1)

    \frac{V}{K+2}

  • Option 2)

    2+\frac{K}{3V}

  • Option 3)

    \frac{2V}{K+2}

  • Option 4)

    \frac{3V}{K+2}

 

Answers (1)
H Himanshu

As we have learned

Parallel Grouping -

C_{eq}=C_{1}+C_{2}+\cdots

- wherein

 

 

Initially                 Equivalent capacitance of the system  


 Total charge  Q= (3C)V 

 Finally                 Equivalent capacitance of the system  

                                                                C_{eq} = KC+2C

Hence common potential      
                                                V= \frac{Q}{(KC+2C)}= \frac{3CV}{(K+2)C}=\frac{3V}{K+2}

 


Option 1)

\frac{V}{K+2}

Option 2)

2+\frac{K}{3V}

Option 3)

\frac{2V}{K+2}

Option 4)

\frac{3V}{K+2}

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