Get Answers to all your Questions

header-bg qa

Which of the following has unpaired electron(s) ?

  • Option 1)

    N2

  • Option 2)

    O_{2}^{-}

  • Option 3)

    N_{2}^{2+}

  • Option 4)

    O_{2}^{2-}

 

Answers (1)

best_answer

As we learned

 

The increasing order of energies for O2 and F2 -

\sigma (1S)<\sigma ^{\ast }(1s)<\sigma (2S)<\sigma ^{\ast }(2S)<\sigma (2P_{Z})<\pi (2P_{_X})=\pi (2P_{Y})<\pi(2P_{X}^{\ast })=\pi(2P_{Y}^{\ast })<\sigma^{\ast }(2P_{Z})

-

 

 

Magnetic behaviour of molecule -

If  all the molecular orbitals in a molecule are doubly occupied, the substance is diamagnetic

- wherein

However if one or more molecular orbital are singly occupied it is paramagnetic e.g. O2

 

 O_{2}^-{} has one impaired electron in \pi _{2pg}^{*} orbital.

Molecular orbital diagram of O_{2}^-{}

 

 

 


Option 1)

N2

Option 2)

O_{2}^{-}

Option 3)

N_{2}^{2+}

Option 4)

O_{2}^{2-}

Posted by

prateek

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE