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# Help me please, A charge Q is uniformly distributed over a long rod AB of length L, as shown in the figure. The electric potential at the poing O lying at a distance L from the end A is :

A charge Q is uniformly distributed over a long rod AB of length L, as shown in the figure. The electric potential at the poing O lying at a distance L from the end A is :

• Option 1)

• Option 2)

• Option 3)

• Option 4)

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N

As we discussed in

Potential Difference -

$\dpi{100} V_{B}-V_{A}=\frac{w}{q}$

-

Charge on the element

$dQ = \frac{Q}{L}dx$

Potential at 0

$dV = \frac{1}{4\pi\epsilon_o}\frac{dQ}{x} = \frac{1}{4\pi\epsilon_o}\frac{Q}{Lx}dx$

$\int dV = \int_{L}^{2L}\frac{1}{4\pi\epsilon_o}\frac{Q}{Lx} dx = \frac{1}{4\pi\epsilon_o}\frac{Q}{L}[lnx]_{L}^{2L}$

$V = \frac{Q ln2}{4\pi\epsilon_o L}$

Option 1)

Option 2)

Option 3)

Option 4)

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