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The number of photo electrons emitted for light of a frequency v (higher than the threshold frequency v_{0} ) is proportional to:

  • Option 1)

    Thershold frequency \left ( v_{0} \right )

  • Option 2)

    Intensity of light

  • Option 3)

    Frequency of light (v)

  • Option 4)

    v-v_{0} \right

 

Answers (1)

best_answer

As we discussed in concept

Energy of a photon -

\fn_jvn E= h\nu = \frac{hc}{\lambda }

- wherein

h= Plank's\: constant

\boldsymbol{\nu= frequency\: of \: radiation }

\lambda \rightarrow wave \: length

 

 Number of photoelectron N=\frac{P \lambda}{hc}=\frac{IA \lambda}{hc}

\therefore\:N\propto I(Intensity \:of \:light)

 


Option 1)

Thershold frequency \left ( v_{0} \right )

This option is incorrect.

Option 2)

Intensity of light

This option is correct.

Option 3)

Frequency of light (v)

This option is incorrect.

Option 4)

v-v_{0} \right

This option is incorrect.

Posted by

divya.saini

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