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#### Based on equation , certain conclusions are written. Which of them is not correct? Option 1) For n = 1, the electron has a more negative energy than it does f or n = 6 which means that the electron is more loosely bound in the smallest allowed orbit. Option 2) The negative sign in equation simply means that the energy of electron bound to the nucleus is lower than it would be if the electrons were at the infinite distance from the nucleus. Option 3) Larger the value of n, the larger is the orbit radius. Option 4) Equation can be used to calculate the change in energy when the electron changes orbit.

As we learnt @9648

The electron is more tightly bound in the smallest allowed orbit. Hence n=1, electron has more negative energy implied smallest orbit electron is more strongly bound.

Option 1)

For n = 1, the electron has a more negative energy than it does f or n = 6 which means that the electron is more loosely bound in the smallest allowed orbit.

Option 2)

The negative sign in equation simply means that the energy of electron bound to the nucleus is lower than it would be if the
electrons were at the infinite distance from the nucleus.

Option 3)

Larger the value of n, the larger is the orbit radius.

Option 4)

Equation can be used to calculate the change in energy when the electron changes orbit.