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The major product of the following reaction is :     \xrightarrow[\left ( ii \right )CH_{3}I]{\left ( i \right )aq.NaOH}

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

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Schotten Baumann reaction -

Benzoylation of compounds containing active hydrogen with benzyl chloride in presence of NaOH.

- wherein

 

 

 

Physical properties of Phenol -

–  Phenols are more acidic than alcohols

–  They are less soluble in water but readily soluble in organic solvents.

–  They liquify due to high hygroscopic nature.

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As we have learned when aq NaOH is used as a catalyst with CH3I.

I- will react with H+ and HI will be the side product .

A2B3 has HCP lattice .

If A form HCP, then \frac{3}{4}th of THV must be occupied by B to form A2B3  ,

If B form HCP, then \frac{1}{3}th of THV must .


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Option 4)

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