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The reaction thst is NOT involve in the ozone layer depletion mechanism in the stratosohere is:

  • Option 1)

    HOCl_{\left ( g \right )}\overset{hv}{\rightarrow}OH_{\left ( g \right )}+Cl_{\left ( g \right )}

     

     

     

  • Option 2)

     

    .\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: .\\* ClO_{\left ( g \right )}+O_{\left ( g\ \right )}\rightarrow Cl_{\left ( g \right )}+O_{2\left ( g \right )}

  • Option 3)

    \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: . \: \: \: \: \: \: \: \: \: \: \: \: \: .\\*CF_{2}Cl_{2\left ( g \right )}\overset{uv}{\rightarrow}Cl_{\left ( g \right )}+CF_{2}Cl_{\left ( g \right )}

  • Option 4)

    CH_{4}+2O_{3}\rightarrow 3CH_{2}=O+3H_{2}O

Answers (1)

best_answer

 

Breakdown of ozone -

CFCs in stratosphere absorbs UV radiations and form chlorine free radical, which continuously breakdown the ozone.

- wherein

CF_{2}Cl_{2}(g)\rightarrow Cl^{0}(g)+C^{0}F_{2}Cl(g)

Cl^{0}(g)+O_{3}\left ( g \right )\rightarrow ClO^{0}(g)+O_{2}(g)

ClO^{0}\left ( g \right )+O^{0}\left ( g \right )\rightarrow Cl^{0}\left ( g \right )+O_{2}\left ( g \right )

As we have learned in ozone layer depletion .

Ozone layer is depleted due to various pollutants and the reaction which is not involved is -

CH_{4} + 2O_{3} \rightarrow 3CH_{2}= O + 3 H_{2}OP

 

 


Option 1)

HOCl_{\left ( g \right )}\overset{hv}{\rightarrow}OH_{\left ( g \right )}+Cl_{\left ( g \right )}

 

 

 

Option 2)

 

.\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: .\\* ClO_{\left ( g \right )}+O_{\left ( g\ \right )}\rightarrow Cl_{\left ( g \right )}+O_{2\left ( g \right )}

Option 3)

\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: . \: \: \: \: \: \: \: \: \: \: \: \: \: .\\*CF_{2}Cl_{2\left ( g \right )}\overset{uv}{\rightarrow}Cl_{\left ( g \right )}+CF_{2}Cl_{\left ( g \right )}

Option 4)

CH_{4}+2O_{3}\rightarrow 3CH_{2}=O+3H_{2}O

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