Q&A - Ask Doubts and Get Answers
Q

Help me solve this - Electrostatics - JEE Main-5


Three capacitances, each of 3 \muF, are  provided. These cannot be combined to provide the resultant capacitance of :

 

  • Option 1)

    1\mu F

  • Option 2)

    2\mu F

  • Option 3)

    4.5\mu F

  • Option 4)

    6\mu F

 
Answers (3)
176 Views
N neha
S Sourav

3

 

As we discussed in concept

Direction of Electric field - 

if

Parallel Grouping -

C_{eq}=C_{1}+C_{2}+\cdots

- wherein

 

 

Due to Positive Charge electric field is always away from the charge.

-

 

 

Direction of Electric field -

 

Due to Negative charge electric field is always towards the charge.

-

 

 i) All are in series combination.

\frac{1}{C_{eq}}= \frac{1}{3}+ \frac{1}{3}+ \frac{1}{3}= 1\mu F

ii) All are in parallel combination. 

C_{eq}= 3+3+3= 9\mu F

iii) Two capacitors in series and one in parallel.

C_{eq}= 2\mu F

iv) C_{eq}= 4.5 \mu F

 


Option 1)

1\mu F

Option 2)

2\mu F

Option 3)

4.5\mu F

Option 4)

6\mu F

Exams
Articles
Questions