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ABC is an equilateral triangle with O as its centre $\vec{F_1}$ , $\vec{F_2}$ and $\vec{F_3}$ represents three forces acting along the sides AB, BC and AC respectively. If the total torque about O is zero the magnitude of $\vec{F_3}$ is:

Option 1)
$\vec F_1+\vec F_2$

Option 2)
$\vec F_1-\vec F_2$

Option 3)
$2(\vec F_1-\vec F_2)$

Option 4)
$2(\vec F_1+\vec F_2)$

Answers (1)

best_answer

As we learnt in

Torque Experienced by the dipole -

$vec{ au }=vec{P} imes vec{E}$

$vec{ au }=PEsin Theta$

$Theta =0^{circ}$ $au =0$

$Theta =frac{pi }{2}$ $au = max^{m}$

- wherein

Taking anticlockwise torque

$F_{1}d+F_{2}d-F_{3}d=0$

$F_{1}+F_{2}=F_{3}$

Option 1)

$\vec F_1+\vec F_2$

Correct

Option 2)

$\vec F_1-\vec F_2$

Incorrect

Option 3)

$2(\vec F_1-\vec F_2)$

Incorrect

Option 4)

$2(\vec F_1+\vec F_2)$

Incorrect

Posted by

Aadil

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