ABC is an equilateral triangle with O as its centre \vec{F_1} , \vec{F_2} and \vec{F_3}represents three forces acting along the sides AB, BC and AC respectively. If the total torque about O is zero the magnitude of \vec{F_3} is:

  • Option 1)

    \vec F_1+\vec F_2

  • Option 2)

    \vec F_1-\vec F_2

  • Option 3)

    2(\vec F_1-\vec F_2)

  • Option 4)

    2(\vec F_1+\vec F_2)

 

Answers (1)

As we learnt in

Torque Experienced by the dipole -

vec{	au }=vec{P}	imes vec{E}

vec{	au }=PEsin Theta

Theta =0^{circ}    	au =0

Theta =frac{pi }{2}             	au = max^{m}

- wherein

 

 

 

Taking anticlockwise torque 

F_{1}d+F_{2}d-F_{3}d=0

F_{1}+F_{2}=F_{3}


Option 1)

\vec F_1+\vec F_2

Correct

Option 2)

\vec F_1-\vec F_2

Incorrect

Option 3)

2(\vec F_1-\vec F_2)

Incorrect

Option 4)

2(\vec F_1+\vec F_2)

Incorrect

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