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  • Help me solve this In a zero- order reaction for every 10° rise of temperature, the rate is doubled. If the temperature is increased from 10°C to 100°C, the rate of the reaction will become :

In a zero- order reaction for every 10° rise of temperature, the rate is doubled. If the temperature is increased from 10°C to 100°C, the rate of the reaction will become :

  • Option 1)

    256 times

  • Option 2)

    512 times

  • Option 3)

    64 times

  • Option 4)

    128 times

 

Answers (1)

best_answer

As we learnt in

At 10 ^{\circ} C rise, rate of reaction increases by 2 times.

\therefore \frac{r_{100^{\circ}C}}{r_{10^{\circ}C}}=(2^{\frac{100-10}{10}})=2^{9} = 512 \:times


Option 1)

256 times

This option is incorrect.

Option 2)

512 times

This option is correct.

Option 3)

64 times

This option is incorrect.

Option 4)

128 times

This option is incorrect.

Posted by

Plabita

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