1/2 [tan sec + log |(tan + sec )|] + c
1/2 [tan + sec - log|(tan + sec )|] + c
1/2 [tan sec - log |(sec - tan )|] + c
none of these
As we learnt
Integration By PARTS -
Let and are two functions then
- wherein
Where is the Ist function is he IInd function |
I = ò sec q sec2q dq
= sec q tan q -ò sec q tan2q dq
= sec q tan q - ò sec3 q dq + ò sec q dq
\ 2I = sec q tan q + log |sec q + tan q| + c
Þ I = 1/2[tan q sec q + log|tan q + sec q|] + c
Option 1)
1/2 [tan sec + log |(tan + sec )|] + c
Option 2)
1/2 [tan + sec - log|(tan + sec )|] + c
Option 3)
1/2 [tan sec - log |(sec - tan )|] + c
Option 4)
none of these
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