Q&A - Ask Doubts and Get Answers
Q

Help me solve this The increasing order of the ionic radii of the given isoelectronic species is :

The increasing order of the ionic radii of the given isoelectronic species is :

  • Option 1)

    Cl^{-},Ca^{2+},K^{+},S^{2-}

  • Option 2)

    S^{2-},Cl^{-},Ca^{2+},K^{+},

  • Option 3)

    Ca^{2+},K^{+},Cl^{-},S^{2-}

  • Option 4)

    K^{+},S^{2-},Ca^{2+},Cl^{-}

 
Answers (4)
316 Views
H hari

3

 

 

 

ca2+<k+<cl-<s2-

option 3)

As learnt in

Size of isoelectronic species -

Smaller the value of z/e, larger the size of that species.Smaller z means effective nuclear charge is small hence size is large.

-

 

 

For isoelectronic species as effective nuclear charge increases, ionic radii decreases. Nuclear charge is maximum of the species with maximum protons. Order of nuclear charge:

  


Option 1)

Cl^{-},Ca^{2+},K^{+},S^{2-}

This option is incorrect.

Option 2)

S^{2-},Cl^{-},Ca^{2+},K^{+},

This option is incorrect.

Option 3)

Ca^{2+},K^{+},Cl^{-},S^{2-}

This option is correct.

Option 4)

K^{+},S^{2-},Ca^{2+},Cl^{-}

This option is incorrect.

Exams
Articles
Questions