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In the nuclear decay given below:

_{Z}^{A}\textrm{X}\rightarrow _{Z+1}^{A}\textrm{Y} \rightarrow _{Z-1}^{A-4}\textrm{B*}\rightarrow _{Z-1}^{A-4}\textrm{B} the particles emitted in the sequence are

  • Option 1)

    \gamma, \beta,\alpha

  • Option 2)

    \beta ,\gamma ,\alpha

  • Option 3)

    \alpha ,\beta ,\gamma

  • Option 4)

    \beta ,\alpha ,\gamma

 

Answers (1)

best_answer

As we learnt in 

? Minus - decay -

^{A}_{Z}X ightarrow _{Z+1}^{A}Y+eta ^{-}+ ar{ u }+Q value

- wherein

ar{ u } ightarrow anti : neutrino

Q: value =left [ M_{X}-M_{Y} ight ]c^{2}

 

 

 

? plus decay -

^{A}_{Z}X ightarrow _{Z-1}^{A}Y+eta ^{+}+ { u }+Q value      

- wherein

u ightarrow : neutrino

Q: value =left [ M_{X}-M_{Y}-2M_{e} ight ]c^{2}

 

 

 \large _{Z}^{A}\textrm{X} \: \: \overset{\beta ^{-}}{\rightarrow} \: \: _{Z+1}^{A}\textrm{Y} \: \: \: \overset{\alpha_{2}^{4}} {\rightarrow} \: \: \: _{Z-1}^{A-4}\textrm{B}^{*} \: \: \: \overset{\gamma }{\rightarrow} \: \: \: _{Z-1}^{A-4}\textrm{B}

 

sequence is \beta , \: \alpha , \: \gamma


Option 1)

\gamma, \beta,\alpha

Incorrect

Option 2)

\beta ,\gamma ,\alpha

Incorrect

Option 3)

\alpha ,\beta ,\gamma

Incorrect

Option 4)

\beta ,\alpha ,\gamma

Correct

Posted by

Aadil

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