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  • Help me understand! - Differential equations - JEE Main-4

Degree of differential equation

\left ( \frac{d^{3}y}{dx^{3}} \right )^{5}+\left ( \frac{d^{3}y}{dx^{3}} \right )^{2}-\left ( \frac{d^{2}y}{dx^{2}} \right )^{10}= x is

  • Option 1)

    10

  • Option 2)

    3

  • Option 3)

    5

  • Option 4)

    2

 

Answers (1)

best_answer

As we learnt 

 

Degree of a Differential Equation -

Degree of Highest order differential coefficient appearing in it, provided it can be expressed as a polynomial equation in derivatives

- wherein

\left ( \frac{dy}{dx} \right )^{2}+3\left ( \frac{dy}{dx} \right )-5=0

Degree = 2

 

 

 

When it is already in form of polynomial equation in derivatives so degree of highest derivative i.e third derivative will be taken. So degree=5.


Option 1)

10

Option 2)

3

Option 3)

5

Option 4)

2

Posted by

Himanshu

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