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An eletromagnetic wave of frequency v=3.0 MHz passes from vacuum into a dielectric medium with relative permittivity \varepsilon =4.0. Then

  • Option 1)

    wavelength is doubled and frequency is unchanged

  • Option 2)

    wavelength is doubled and frequency becomes half

  • Option 3)

    wavelength is halved and frequency remains unchanged

  • Option 4)

    wavelength and frequency both remain unchanged

 

Answers (1)

best_answer

 

Wavelength of EM Wave -

lambda =frac{lambda_{o}}{mu}

- wherein

lambda _{o} = Wavelength in vacuum

mu = Refractive index of medium

 

 frequency of an electromagnetic wave is independent of medium 

\lambda =\frac{\lambda _{o}}{\mu }\\ \mu =\sqrt{\epsilon _{r}}=2\\ \therefore \:\lambda =\frac{\lambda _{o}}{2 } and frequency is unchanged 


Option 1)

wavelength is doubled and frequency is unchanged

This solution is incorrect 

Option 2)

wavelength is doubled and frequency becomes half

This solution is incorrect 

Option 3)

wavelength is halved and frequency remains unchanged

This solution is correct 

Option 4)

wavelength and frequency both remain unchanged

This solution is incorrect 

Posted by

divya.saini

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