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  • Help me understand! How long (approximate) should water be electrolysed by passing through 100 amperes current so that the oxygen released can completely burn 27.66 g of diborane ?(Atomic weight of B=10.8 u)

How long (approximate) should water be electrolysed by passing through 100 amperes current so that the oxygen released can completely burn 27.66 g of diborane ?

(Atomic weight of B=10.8 u)

  • Option 1)

    1.6 hours
     

  • Option 2)

     6.4 hours
     

  • Option 3)

     0.8 hours
     

  • Option 4)

     3.2 hours

 

Answers (1)

best_answer

 

As we learned

Faraday's first law of electrolysis -

The mass of any substance deposited or dissolved at any electrode during electrolysis is directly propotional to the quantity of electricity passed through the solution.

- wherein

W\alpha\ Q

W = Z I t

Z = mass of electrolyte get deposited

Z = electro chemical equivalent

 

 B_{2}H_{6}+3O_{2}\rightarrow B_{2}O_{3}+3H_{2}O

No. of moles of B_{2}H_{6}= \frac{22.66}{22.66}= 1mole

So 3 mole of O2 is required

2H_{2}O\rightarrow O_{2}+4H^{+}+4e^{-}

              n -factor =4

 

Meq. Of charge = Meq. Of substance

\Rightarrow \frac{100\times t}{96500}\times 1000= 3\times 4\times 1000

\therefore t=11580\: sec;3.2\: hrs


Option 1)

1.6 hours
 

Option 2)

 6.4 hours
 

Option 3)

 0.8 hours
 

Option 4)

 3.2 hours

Posted by

Plabita

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