Get Answers to all your Questions

header-bg qa

The anodic half -cell battery is recharged using  electicity of 0.05 faraday .The amount of PbSO_{4} electrolyzwd in g during the process is ;(Molar mass of PbSO_{4}=303g\, \, mol^{-1})

  • Option 1)

    22.8

  • Option 2)

    15.2

  • Option 3)

    7.6

  • Option 4)

    11.4

Answers (1)

best_answer

 

Reduction Half Reaction -

The half reaction that involve gain of electrons are called reduction half reaction.

- wherein

e.g. Cl_{2}(g) + 2e^{^{-}}\rightarrow 2Cl^{-}(g)

 

 

 

Oxidation Half Reaction -

Half reaction that involves loss of electrons are called oxidation half reactions

- wherein

e.g.2Na (s)\rightarrow 2Na^{+}(g) + 2e^{-}

 

 

 

Half Reaction Method -

1. Produce unbalanced equation for the reaction in ionic form.

2. Separate the equation into half reactions.

3. Balance the atoms other than O and H in each half reaction.

4. Add H_{2}O to balance O atoms and H^{+} to balance H atom.

5. Add electrons to one side of the half reaction to balance the charges.

as we know that PbSO_{4}+2e^{-}\rightarrow Pb_{\left ( s \right )}+SO_{4}^{2-}  when 2e-,2F current passed electrolyzed PbSO_{4}-=330gm/mol

so, 0.0f current passed  then electrolyzedPbSO_{4} will  be =\frac{303}{2\times 0.05}=7.6g

 

   


Option 1)

22.8

Option 2)

15.2

Option 3)

7.6

Option 4)

11.4

Posted by

admin

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE