The pair of metal ions that can give a spin-only magnetic moment of 3.9 BM for the complex [M(H_{2}O)_{6}]Cl_{2}, is :

  • Option 1)

    Co^{2+}\: and \: Fe^{2+}

     

  • Option 2)

    V^{2+}\: and\; Co^{2+}

  • Option 3)

    V^{2+}\: and\; Fe^{2+}

  • Option 4)

    Cr^{2+}\: and\; Mn^{2+}

Answers (1)
A admin

 

Magnetic Moments (spin only) -

\sqrt{n\left ( n+2 \right )} where n= number of the unpaired electron.

- wherein

Number of unpaired e^{-} s and corresponding magnetic moments

1\rightarrow 1.7\\2\rightarrow 2.8\\3\rightarrow 3.9\\4\rightarrow 4.9\\5\rightarrow 5.9

as we knoe that

we haew iearned in crystalfield theory  accoeding to CFT ,H2O is a weak ligand

Fe^{2+}= t_{2g}^{211}eg^{11}\, \, \, \, FOr V^{2+}\left [ Ar \right ]_{18}----3d^{3}

CO^{2+}= t_{2g}^{221}eg^{11}

V^{2+}= t_{2g}^{111}\, eg^{00}\, \, For \, \, CO^{2+}\left [ Ar \right ]_{18}---3d^{7}:

3unpaired electron spin only magnetic moment= 3.89 BM

 


Option 1)

Co^{2+}\: and \: Fe^{2+}

 

Option 2)

V^{2+}\: and\; Co^{2+}

Option 3)

V^{2+}\: and\; Fe^{2+}

Option 4)

Cr^{2+}\: and\; Mn^{2+}

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