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# Help me understand! Two charges equal in magnitude and opposite in polarity are placed at a certain distance apart and force acting between them is F. If 75% charge of one is transferred to another, then the force between the charges becomes

Two charges equal in magnitude and opposite in polarity are placed at a certain distance apart and force acting between them is F. If 75% charge of one is transferred to another, then the force between the charges becomes

• Option 1)

$\frac{F}{16}\;$

• Option 2)

$\; \frac{9F}{16}\; \;$

• Option 3)

$\; F\; \;$

• Option 4)

$\; \frac{15}{16}F$

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As we learned

Coulomb's Law -

The force of attraction or repulsion is directly proportional to product of their two charges and inversly proportional to square distance between them.

-

Initially  $F=k\frac{Q^{2}}{r^{2}}\; \; \; \; \; \; \; Finally\; F'=\frac{k.(\frac{Q}{4})^{2}}{r^{2}}=\frac{F}{16}$

Option 1)

$\frac{F}{16}\;$

Option 2)

$\; \frac{9F}{16}\; \;$

Option 3)

$\; F\; \;$

Option 4)

$\; \frac{15}{16}F$

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