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How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms? atA.

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8 moles oxygen ———→ 1 mol of Mg3(PO4)2

1 mol of O ———→ 1/8 mol of Mg3(PO4)2

0.25 mol of Oxygen ——→ 1/8 x 25/100 mol of Mg3(PO4)2

………………………………….. => 1/32 mol of Mg3(PO4)2

………………………………….. => 0.03125 M of Mg3(PO4)2

…………………………………. => 3.125 x 10^(-2)

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Amit Kumar

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8 moles oxygen ———→ 1 mol of Mg3(PO4)2

1 mol of O ———→ 1/8 mol of Mg3(PO4)2

0.25 mol of Oxygen ——→ 1/8 x 25/100 mol of Mg3(PO4)2

                                                => 1/32 mol of Mg3(PO4)2

                                                => 0.03125 M of Mg3(PO4)2

                                               => 3.125 x 10^(-2)

Posted by

Amit Kumar

View full answer