# how to solve A body is executing SHM with amplitude A and time period T. The ratio of kinetic energy when displacement from equilibrium position is half the amplitude and 1/4th amplitude isA body is executing SHM with amplitude A and time period T. The

Amplitude = A

Total Energy of SHM = E =

Let the spring constant be k

Potetial energy when displacement from equilibrium position is x

Potetial energy when displacement from equilibrium position is half the amplitude = U1

Kinetic energy when displacement from equilibrium position is half the amplitude = K1 = E - U1

Potetial energy when displacement from equilibrium position is one-fourth the amplitude = U2

Kinetic energy when displacement from equilibrium position is one-fourth the amplitude = K2 = E - U2

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