0.5 moles of gas A and x moles of gas B exert a pressure of 200 Pa in a container of volume 10m³at 1000 K .Given R is the gas constant in JK^-1mol^-1 , x is:
Option 1)
$\frac{2R}{4+R}$

Option 2)
$\frac{2R}{4-R}$
Option 3)
$\frac{4+R}{2R}$
Option 4)
$\frac{4-R}{2R}$

Answers (1)

A admin

Partial Pressure of a gas in gaseous mixture -

Partial Pressure = (Total Pressure of Mixture) $\times$ (mole fraction of gas)

Critical Volume -

volume of gas-liquid equilibrium at critical pressure and temperature

- As we know the formula $PV=n_{T}RT$

here $n_{T}=0.5+X$

200 $\times$ 10=(0.5x) $\times$ R $\times$ 1000

2=(0.5+x)R

$X=\frac{2}{R}-0.5$

$X= \frac{4-R}{2R}$

the correct option is $X= \frac{4-R}{2R}$

$\times$

Option 1)

$\frac{2R}{4+R}$

Option 2)

$\frac{2R}{4-R}$

Option 3)

$\frac{4+R}{2R}$

Option 4)
$\frac{4-R}{2R}$

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0.5 moles of gas A and x moles of gas B exert a pressure of 200 Pa in a container of volume 10m3at 1000 K .Given R is the gas constant in JK-1 mol-1 , x is:Option 1) Option 2)Option 3)Option 4)

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0.5 moles of gas A and x moles of gas B exert a pressure of 200 Pa in a container of volume 10m³at 1000 K .Given R is the gas constant in JK^-1mol^-1 , x is:
Option 1)
$\frac{2R}{4+R}$

Option 2)
$\frac{2R}{4-R}$
Option 3)
$\frac{4+R}{2R}$
Option 4)
$\frac{4-R}{2R}$