0.5 moles of gas A and x moles of gas B exert a pressure of 200 Pa in a container of volume 10m3at 1000 K .Given R is the gas constant in JK-1 mol-1 , x is:

  • Option 1)

    \frac{2R}{4+R}

     

     

  • Option 2)

    \frac{2R}{4-R}

  • Option 3)

    \frac{4+R}{2R}

  • Option 4)

    \frac{4-R}{2R}

Answers (1)
A admin

 

Partial Pressure of a gas in gaseous mixture -

Partial Pressure = (Total Pressure of Mixture) \times (mole fraction of gas)

 

 

Critical Volume -

volume of gas-liquid equilibrium at critical pressure and temperature

- As we know the formula PV=n_{T}RT

here n_{T}=0.5+X

200\times10=(0.5x) \timesR\times1000

2=(0.5+x)R

X=\frac{2}{R}-0.5

X= \frac{4-R}{2R}

the correct option is X= \frac{4-R}{2R}

 

 

 

-

\times

 

 


Option 1)

\frac{2R}{4+R}

 

 

Option 2)

\frac{2R}{4-R}

Option 3)

\frac{4+R}{2R}

Option 4)

\frac{4-R}{2R}

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