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# How to solve this problem- - A dsorption of gas follows Freundlich adsorbtin isotherm. In the given plox ,x is the mass of the ga - Surface Chemistry - JEE Main

A dsorption of gas follows Freundlich adsorbtin isotherm. In the given plox ,x is the mass of the gas  adsorbent at pressure P.   $\frac{x}{m}$  is propotional to:

• Option 1)

$p^{2}$

• Option 2)

$p^{\frac{1}{4}}$

• Option 3)

$p^{\frac{1}{2}}$

• Option 4)

$p$

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Freundlich adsorption isotherm -

Freundlich gave an empirical relationship between the quantity of gas adsorbed by a unit mass of solid adsorbent and pressure at a particular temperature

- wherein

$\frac{x}{m}= K.p^{1/n}$ (n>1)

As we know that:

From the graph $\frac{x}{m}= K\left ( p \right )^{\frac{1}{2}}\left ( theorem \right )$

$log\frac{x}{m}= log K+\frac{1}{n}log P$

$m= \frac{y}{x}\left ( slope \right ),\frac{1}{n}is\, \, slope,\frac{1}{n}= \frac{2}{4}= > n= 2$

$\frac{x}{m}= KP^{\frac{1}{2}}= > \frac{x}{m}\propto P^{\frac{1}{2}}$

Logarithmic graph of Freundlich isotherm -

$log\frac{x}{m}= log K+\frac{1}{n}log p$

- wherein

The slope of the straight line gives the value of 1/n. The intercept on y-axis gives the value of log K.

Option 1)

$p^{2}$

Option 2)

$p^{\frac{1}{4}}$

Option 3)

$p^{\frac{1}{2}}$

Option 4)

$p$

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