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How to solve this problem- - Chemical Bonding and Molecular Structure - JEE Main-2

In XeO3F2 , the number of bond pair(s),
\pi-bond(s) and lone pair(s) on Xe atom
respectively are :

  • Option 1)

    5, 2, 0

  • Option 2)

    4, 2, 2

  • Option 3)

    5, 3, 0

  • Option 4)

    4, 4, 0

 
Answers (1)
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As we have learnt,

 

Dettermination of shape of molecules using VSEPR Theory -

calculate \:X

X=(No.\;of\:valence\:electrons\:of\:central\:atom\:)+(No.\:of\:other\:atom\:)+(Negative\:charge\:on\:the\:molecule)-(Positive\:charge\:on\:the\:molecule)

-

 

 

 

5 sigma bond, 3 \pi bonds & zero lone pair in Xe.


Option 1)

5, 2, 0

Option 2)

4, 2, 2

Option 3)

5, 3, 0

Option 4)

4, 4, 0

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