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Two cities are 150 km apart. Electric power is sent from one city to another city through copper wires. The fall of potential per km is 8 volt and the average resistance per km is 0.5 \Omega. The power loss in the wire is :

  • Option 1)

    19.2 W

  • Option 2)

    19.2 kW

  • Option 3)

    19.2 J

  • Option 4)

    12.2 kW

 

Answers (1)

best_answer

As we learnt in @8122

Total resistance, R = \left ( 0.5\:\Omega /km \right )\times \left ( 150 km \right ) = 75\:\Omega

Total voltage drop = (8 V/km) x (150 km) = 1200 V

Power loss = \frac{\left ( \Delta V \right )^{2}}{R} = \frac{\left ( 1200 \right )^{2}}{75} = 19200\:W = 19.2 \:kW


Option 1)

19.2 W

This answer is incorrect

Option 2)

19.2 kW

This answer is correct

Option 3)

19.2 J

This answer is incorrect

Option 4)

12.2 kW

This answer is incorrect

Posted by

divya.saini

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