Two cities are 150 km apart. Electric power is sent from one city to another city through copper wires. The fall of potential per km is 8 volt and the average resistance per km is 0.5 \Omega. The power loss in the wire is :

  • Option 1)

    19.2 W

  • Option 2)

    19.2 kW

  • Option 3)

    19.2 J

  • Option 4)

    12.2 kW

 

Answers (1)

As we learnt in @8122

Total resistance, R = \left ( 0.5\:\Omega /km \right )\times \left ( 150 km \right ) = 75\:\Omega

Total voltage drop = (8 V/km) x (150 km) = 1200 V

Power loss = \frac{\left ( \Delta V \right )^{2}}{R} = \frac{\left ( 1200 \right )^{2}}{75} = 19200\:W = 19.2 \:kW


Option 1)

19.2 W

This answer is incorrect

Option 2)

19.2 kW

This answer is correct

Option 3)

19.2 J

This answer is incorrect

Option 4)

12.2 kW

This answer is incorrect

Preparation Products

JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Knockout JEE Main April 2021 (Easy Installments)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 4999/-
Buy Now
Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Knockout BITSAT 2021

It is an exhaustive preparation module made exclusively for cracking BITSAT..

₹ 4999/- ₹ 2999/-
Buy Now
Exams
Articles
Questions