# A piece of cloud having area $25\times 10^{6}m^2$ and electric potential of 105 volts. If the height of cloud is 0.75 km, then energy of electric field between earth and cloud will be Option 1) 250 J Option 2) 750 J Option 3) 1225 J Option 4) 1475 J

V Vakul

As we have learnt,

If place in a Medium with dielectric constant -

$\dpi{100} U_{v}=\frac{1}{2}\epsilon _{0}\epsilon _{r}E^{2}$

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Energy

$\\*=\frac{1}{2}\epsilon_0\times (A\times d) = \frac{1}{2}\epsilon_0\left (\frac{V^2}{d^2} \right )Ad = \frac{1}{2}\times \frac{8.85\times10^{-12}\times (10^{5})^{2}\times 25\times 10^6}{0.75\times 10^3} \\*=1475J$

Option 1)

250 J

Option 2)

750 J

Option 3)

1225 J

Option 4)

1475 J

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