A piece of cloud having area 25\times 10^{6}m^2 and electric potential of 105 volts. If the height of cloud is 0.75 km, then energy of electric field between earth and cloud will be

  • Option 1)

    250 J

  • Option 2)

    750 J

  • Option 3)

    1225 J

  • Option 4)

    1475 J

 

Answers (1)
V Vakul

As we have learnt,

 

If place in a Medium with dielectric constant -

U_{v}=\frac{1}{2}\epsilon _{0}\epsilon _{r}E^{2}

-

 

 Energy

\\*=\frac{1}{2}\epsilon_0\times (A\times d) = \frac{1}{2}\epsilon_0\left (\frac{V^2}{d^2} \right )Ad = \frac{1}{2}\times \frac{8.85\times10^{-12}\times (10^{5})^{2}\times 25\times 10^6}{0.75\times 10^3} \\*=1475J

 


Option 1)

250 J

Option 2)

750 J

Option 3)

1225 J

Option 4)

1475 J

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