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Oxidation number of P in PO_{4}^{3-}, of S in SO_{4}^{2-} and that of Cr_{2}\ O_{7}^{2-} are respectively

  • Option 1)

    +3, +6 and +5

  • Option 2)

    +5, +3 and +6

  • Option 3)

    -3, +6 and +6

  • Option 4)

    +5, +6 and +6

 

Answers (1)

best_answer

As we learnt in

Rules for Oxidation Number -

The algebraic sum of the oxidation number of all the atoms in a compound must be zero. In polyatomic ion the sum is equal to charge on the ion.

-

 

 Sum of oxidation number =charge on the ion.

 In \ po_{4}^{3^{-}}: x+4 \times (-2)=-3 \Rightarrow x=5

In \ So_{4}^{2^{-}}: x+4 \times (-3)=-2 \Rightarrow x=6

In \ Cr_{2}O 7^{2^{-}}: 2x+7 \times (-2)=-2 \Rightarrow x=6

 


Option 1)

+3, +6 and +5

Incorrect

Option 2)

+5, +3 and +6

Incorrect

Option 3)

-3, +6 and +6

Incorrect

Option 4)

+5, +6 and +6

correct

Posted by

divya.saini

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