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The de-Broglie wavelength of a particle of mass 6.63 g moving with a velocity of 100 ms-1 is :            

 

  • Option 1)

    10^{-33}m

  • Option 2)

    10^{-35}m

  • Option 3)

    10^{-31}m

  • Option 4)

    10^{-25}m

 

Answers (2)

best_answer

As discussed in concept

De-broglie wavelength -

\lambda = \frac{h}{mv}= \frac{h}{p}

- wherein

where m is the mass of the particle

v its velocity 

p its momentum

 

 E = \frac {6.62\times10^{-34}} {6.62\times10^{-3}\times 100}

E = 10^{-33} m

Answer: Correct option 1

 


Option 1)

10^{-33}m

This is the correct option

Option 2)

10^{-35}m

This is incorrect

Option 3)

10^{-31}m

This option is incorrect

Option 4)

10^{-25}m

This is incorrect

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