Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • I have a doubt, kindly clarify. - Current Electricity - NEET

A cell having an emf \epsiv\epsiv and internal resistance r is connected across a variable external resistance R. As the resistance R is increased, the plot of potential difference V across R is given by:

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

 

Answers (1)

best_answer

As discussed in 

Current in the circuit I=\frac{\epsilon }{R+r}

Potential difference across R:    V=IR=\left( \frac{\epsilon}{R+r} \right )R

When, 

R=0, \:\:\:\:\:V=0

R=\alpha , \:\:\:\:\:V=\epsilon


Option 1)

This option is incorrect.

Option 2)

This option is correct.

Option 3)

This option is incorrect.

Option 4)

This option is incorrect.

Posted by

divya.saini

View full answer

Similar Questions

Latest Question