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# I have a doubt, kindly clarify. - If a straight line passing through the point is such that its intercepted portion between the coord - Co-ordinate geometry - JEE Main

If a straight line passing through the point $P(-3,4)$ is such that its intercepted portion between the coordinates axes is bisected at P, then its equation is :

• Option 1)

$4x+3y=0$

• Option 2)

$4x-3y+24=0$

• Option 3)

$x-y+7=0$

• Option 4)

$3x-4y+25=0$

Views

x-intercept -

The distance on the x-axis from the origin where the straight line cuts it.

- wherein

Intercept form of a straight line -

$\frac{x}{a}+\frac{y}{b}=1$

- wherein

$a$ and $b$ are the $x$-intercept and $y$ -intercept respectively.

So that line say intersect y-axis at (o,b ) and x-axis at (a,o).

since it is bisected at p (-3,4)

$\Rightarrow a=2\times \left ( -3 \right )$

$=-6\\\\b=2\times 4\\\\=8\\\\Equation \: \: of\: \: line -\\\\\frac{x}{a} +\frac{y}{b}=1\\\\\frac{x}{-6}+\frac{y}{8}=1 \\\\\Rightarrow 4x-3y+24=0$

Option 1)

$4x+3y=0$

Option 2)

$4x-3y+24=0$

Option 3)

$x-y+7=0$

Option 4)

$3x-4y+25=0$

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