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  • I have a doubt, kindly clarify. - solution is added to 30 mL of solution. The of resultant mixture is - Some basic concepts in chemistry - JEE Main

20 mL\, o\! f \: 0.1M H_{2}SO_{4} solution is added to 30 mL of 0.2 NH_{4}OH solution. ThepH of resultant  mixture is \left [ pk_{b}\, \, of\, \, NH_{4}OH=4.7 \right ]

 

 

  • Option 1)

    5.2

  • Option 2)

    9.0

  • Option 3)

    5.0

  • Option 4)

    9.4

Answers (1)

best_answer

 

Molality -

Molality (m) = (number of moles of solute)/(mass of solvent in kg)

 

- wherein

It is defined as the number of moles of solute present in 1 kg of solvent. It is denoted by m.

As we know that:H_{2}SO_{4}+2NH_{4}OH\rightarrow \left ( NH_{4} \right )_{2}SO_{4}+2H_{2}O

20\times 0.2=2m mole\, \, \, 30\times 0.2=6 m mole

final   0      2mmol →2mmol

P^{OH}=P^{Kb}+log\frac{NH_{4}^{+}}{NH_{4}OH}

==P^{Kb}+log\frac4{2}\left [ 2mmol \times 2\left ( NH_{4} ^{+}=4\right ) \right ]

4.7+log^{2}= 4.7+0.3= 5

P^{4}= 14-5= 9

 

 


Option 1)

5.2

Option 2)

9.0

Option 3)

5.0

Option 4)

9.4

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