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Three masses are placed on the x-axis: 300 g at origin, 500 g at x = 40 cm and 400 g at x = 70 cm. The distance of the centre of mass from the origin is:

  • Option 1)

    45 cm

  • Option 2)

    50 cm

  • Option 3)

    30 cm

     

  • Option 4)

    40 cm

 

Answers (1)

As we learnt in

Centre of mass when some mass is added in the body -

{vec{r}_{CM}}=frac{m_{1}vec{r_{1}}+{m_{2}}vec{r}_{2}}{m_{1}+m_{2}}

- wherein

m1 &  vec{r_{1}} are mass and position of centre of mass for whole body. m2 & vec{r_{2}} are mass and position of centre of mass of added mass.

 

 

 

X_{cm}=\frac{m_{1}X_{1}+m_{2}X_{2}+m_{3}X_{3}}{m_{1}+m_{2}+m_{3}}

X_{cm}=\frac{300\times 0+500\times 40+400 \times 70}{300+500+400}

Xcm =40 CM


Option 1)

45 cm

This is incorrect option

Option 2)

50 cm

This is incorrect option

Option 3)

30 cm

 

This is incorrect option

Option 4)

40 cm

This is correct option

Posted by

Vakul

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