Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

Which is diamagnetic?

Option 1)
$\left [ Fe(CN)_{6} \right ]^{3-}$

Option 2)
$\left [ Co(F_{6}) \right ]^{3-}$

Option 3)
$\left [ Ni(CN)_{4} \right ]^{2-}$

Option 4)
$\left [ Ni(Cl)_{4} \right ]^{-2}$

Answers (1)

As we learnt in

Magnetic Moments (spin only) -

$\sqrt{n\left ( n+2 \right )}$ where n= number of unpaired electron.

- wherein

Number of unpaired $e^{-} s$ and corresponding magnetic moments

$\\1\rightarrow 1.7\\2\rightarrow 2.8\\3\rightarrow 3.9\\4\rightarrow 4.9\\5\rightarrow 5.9$

Electronic configuration of Ni²⁺ : 3d⁸ 4s⁰ 4p⁰

Since CN^- is a strong field ligand, so electron in 3d orbitals will pair up.

Electronic configuration of Ni²⁺ in [Ni(CN)₄]^2- :

Since there are no unpaired electrons, so the complex is diamagnetic in nature.

Option 1)

$\left [ Fe(CN)_{6} \right ]^{3-}$

Incorrect

Option 2)

$\left [ Co(F_{6}) \right ]^{3-}$

Incorrect

Option 3)

$\left [ Ni(CN)_{4} \right ]^{2-}$

Correct

Option 4)

$\left [ Ni(Cl)_{4} \right ]^{-2}$

Incorrect

Posted by

Vakul

View full answer

Similar Questions

Latest Question