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Which one of the following complex ions is expected to absorb visible light?

(At. no. Zn=0, Sc=21, Ti=22, Cr=24)

  • Option 1)

    \left [ Ti(en)_{2}(NH_{3})_{2} \right ]^{4+}

  • Option 2)

    \left [ Cr(NH_{3})_{6} \right ]^{3+}

  • Option 3)

    \left [ Zn(NH_{3})_{6} \right ]^{2+}

  • Option 4)

    \left [ Sc(H_{2}O)_{3}(NH_{3})_{3} \right ]^{3+}

 

Answers (1)

As we learnt in 

Magnetic Moments (spin only) -

\sqrt{n\left ( n+2 \right )} where n= number of unpaired electron.

- wherein

Number of unpaired e^{-} s and corresponding magnetic moments

1\rightarrow 1.7\\2\rightarrow 2.8\\3\rightarrow 3.9\\4\rightarrow 4.9\\5\rightarrow 5.9

 

 

Colour in coordination compounds -

The colour of the complex is complimentary to that which is absorbed

-

 

A couple absorbs light (visible) when it has unpaired electrons of all the complexes given \left [ Cr(NH_{3})_{6} \right ]^{3+} has unpaired electrons  while others have none. Electronic config of Cr3+

 


Option 1)

\left [ Ti(en)_{2}(NH_{3})_{2} \right ]^{4+}

This solution is incorrect 

Option 2)

\left [ Cr(NH_{3})_{6} \right ]^{3+}

This solution is correct 

Option 3)

\left [ Zn(NH_{3})_{6} \right ]^{2+}

This solution is incorrect 

Option 4)

\left [ Sc(H_{2}O)_{3}(NH_{3})_{3} \right ]^{3+}

This solution is incorrect 

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