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# I have a doubt on this

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For a diatomic gas the ratio of two specific heat Cp/Cv is equal to

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Degrees of freedom of diatomic gas, f = 5

$C_{V}=\frac{fR}{2}=\frac{5R}{2}$

$C_{P}=\frac{(f+2)R}{2}=\frac{7R}{2}$

$\\\gamma =\frac{C_{P}}{C_{V}}\\ \gamma =\frac{\frac{7R}{2}}{\frac{5R}{2}}\\ \gamma =\frac{7}{5}\\ \gamma =1.4$

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