Graph between the square of velocity (v) of a particle and the distance (s) moved is shown in figure. The acceleration of the particle in kilometers per hour square is:

Answers (1)

By using the 3rd equation of Velocity –displacement equation -

V^{2}-u^{2}=2as

V\rightarrow Final Velocity = 4600

s\rightarrow Displacement

u\rightarrowInitial velocity = 950

a\rightarrowacceleration

-

 

 We use V2 = u2 + 2as

V2 - u2 = 2as
By putting the values in above equation and solving we get 
a = 3041.6 

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