Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • I need help with - A parallel plate capacitor with plates of area 1m2each, are at a separation of 0.1 m. If the electr - Electrostatics - JEE Main

A parallel plate capacitor with plates of area 1m2 each, are at a separation of 0.1 m. If the electric field between the plates is 100 N/C , the magnitude of charge on each plate is : 

(Take \epsilon _{0} = 8.85 \times 10^{-12} \frac{C^{2}}{N-m^{2}} )

  • Option 1)

    9.85 X 10-10 C

  • Option 2)

    8.85 X 10-10 C

  • Option 3)

    7.85 X 10-10 C

  • Option 4)

    6.85 X 10-10 C

Answers (1)

best_answer

 

Infinite Plane Parallel sheets of charge -

If  

 \sigma _{A}=\sigma _{B}=\sigma \rightarrow \left | E_{p} \right |=\left | E_{R} \right |=\frac{\sigma }{\epsilon _{0}}

and  EQ = 0

-

 

A = 1m2

d= 0.1m

E = 100 N/C

\varepsilon _{0}= 8.85\times 10^{-12}\left ( \frac{C^{2}}{Nm^{2}} \right )

E = \frac{\sigma }{\varepsilon _{0}} = \frac{Q}{A\varepsilon _{0}}

Q = AE\varepsilon _{0}= 1\times 100\times \left ( 8.85\times 10^{-12} \right )=8.85\times 10^{-10}C

 

 

 


Option 1)

9.85 X 10-10 C

Option 2)

8.85 X 10-10 C

Option 3)

7.85 X 10-10 C

Option 4)

6.85 X 10-10 C

Posted by

admin

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024: NTA debars 39 candidates for 3 years on account of using unfair means
anam-khan

JEE Main 2024 session 2 paper 2 answer key objection window closes today; fees
anam-khan

JEE Main 2024 Topper: Farmer’s son Gajare Nilkrishna says ‘keep questioning until you understand’

Latest Question