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  • I need help with A sphere of 4 cm radius is suspended within a hollow sphere of 6 cm radius. The inner sphere is charged to a potential 3 e.s.u. When the outer sphere is earthed. The charge on the inner sphere is

A sphere of 4 cm radius is suspended within a hollow sphere of 6 cm radius. The inner sphere is charged to a potential 3 e.s.u. When the outer sphere is earthed. The charge on the inner sphere is

  • Option 1)

    54 e.s.u.

     

     

     

  • Option 2)

    \frac{1}{4}e.s.u

  • Option 3)

    30 e.s.u

  • Option 4)

    36 e.s.u.

 

Answers (2)

best_answer

As we learned 

 

Potential Due to 2 Concentric Spheres -

If two concentric conducting shells of radii r1 and r2(r2 > r1) carrying uniformly distributed charges Q1 and Q2 respectively

- wherein

Potential at the surface of inner shell is

V_{1}= \frac{1}{4\pi \varepsilon _{0}}\cdot \frac{Q_{1}}{r_{1}}+ \frac{1}{4\pi \varepsilon _{0}}\cdot \frac{Q_{2}}{r_{2}}

and potential at the surface of outer shell

V_{1}= \frac{1}{4\pi \varepsilon _{0}}\cdot \frac{Q_{1}}{r_{1}}+ \frac{1}{4\pi \varepsilon _{0}}\cdot \frac{Q_{2}}{r_{2}}

 

 

Let charge on inner sphere be +Q. charge induced on the inner surface of outer sphere will be –Q.

So potential at the surface of inner sphere (in CGS)

3=\frac{Q}{4}-\frac{Q}{6}

\Rightarrow Q=36 e.s.u.

 

 


Option 1)

54 e.s.u.

 

 

 

Option 2)

\frac{1}{4}e.s.u

Option 3)

30 e.s.u

Option 4)

36 e.s.u.

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