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charge Q is placed at a distance a/2
above the centre of the square surface of
edge a as shown in the figure

The electric flux through the square
surface is :

  • Option 1)

    \frac{Q}{\epsilon_{0}}

     

     

     

  • Option 2)

    \frac{Q}{2\epsilon_{0}}

  • Option 3)

    \frac{Q}{3\epsilon_{0}}

  • Option 4)

    \frac{Q}{6\epsilon_{0}}

 

Answers (2)

best_answer

As we learned 

 

Gauss's Law -

Total flux linked with a closed surface called Gaussian surface.

Formula:

\phi = \oint \vec{E}\cdot d\vec{s}=\frac{Q_{enc}}{\epsilon _{0}}

 

- wherein

No need to be a real physical surface.

Qenc - charge enclosed by closed surface.

 

 We can construct a cube with side a & charge Q at its centre

then total flux = \frac{Q}{\epsilon _{0}}

flux through one side = \frac{Q}{6\epsilon _{0}}


Option 1)

\frac{Q}{\epsilon_{0}}

 

 

 

Option 2)

\frac{Q}{2\epsilon_{0}}

Option 3)

\frac{Q}{3\epsilon_{0}}

Option 4)

\frac{Q}{6\epsilon_{0}}

Posted by

Aadil

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