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I need help with - Temperature difference of C is maintained between two ends of a uniform rod AB of length 2L. Anothe - Properties of Solids and Liquids - JEE Main

Temperature difference of $120^{\circ}$ C is maintained between two ends of a uniform rod AB of length 2L. Another bent rod PQ, of same cross-section as AB and length $\frac{3L}{2},$ is connected across AB (See figure). In steady state, temperature difference between P and Q will be close to :

• Option 1)

$45^{\circ}C\; \;$

• Option 2)

$75^{\circ}C\; \;$

• Option 3)

$60^{\circ}C\; \;$

• Option 4)

$35^{\circ}C\; \;$

Views

Heat Current -

$I_{H}=\frac{\theta_{1}-\theta_{2}}{R_{th}}$

- wherein

$\theta_{1}-\theta_{2}=$ Temperature difference between two ends of the conductor.

Thermal current = $\frac{\theta _{A} - \theta_{B}}{R_{eq}}$

= $\frac{\theta _{A} - \theta_{B}}{\frac{8R}{5}} = \frac{5 \times 120}{8 \times R } = \frac{75}{R}$

$\theta_{p} - \theta_{Q} = \frac{75}{R} . \frac{3R}{5}$

= 45 oC

Option 1)

$45^{\circ}C\; \;$

Option 2)

$75^{\circ}C\; \;$

Option 3)

$60^{\circ}C\; \;$

Option 4)

$35^{\circ}C\; \;$

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