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I need help with - Temperature difference of C is maintained between two ends of a uniform rod AB of length 2L. Anothe - Properties of Solids and Liquids - JEE Main

Temperature difference of 120^{\circ} C is maintained between two ends of a uniform rod AB of length 2L. Another bent rod PQ, of same cross-section as AB and length \frac{3L}{2}, is connected across AB (See figure). In steady state, temperature difference between P and Q will be close to :

  • Option 1)

    45^{\circ}C\; \;

     

     

     

     

     

  • Option 2)

    75^{\circ}C\; \;

  • Option 3)

    60^{\circ}C\; \;

  • Option 4)

    35^{\circ}C\; \;

Answers (1)
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A admin

 

Heat Current -

I_{H}=\frac{\theta_{1}-\theta_{2}}{R_{th}}

 

- wherein

\theta_{1}-\theta_{2}= Temperature difference between two ends of the conductor. 

 

 

Thermal current = \frac{\theta _{A} - \theta_{B}}{R_{eq}}

= \frac{\theta _{A} - \theta_{B}}{\frac{8R}{5}} = \frac{5 \times 120}{8 \times R } = \frac{75}{R}

\theta_{p} - \theta_{Q} = \frac{75}{R} . \frac{3R}{5}

= 45 oC


Option 1)

45^{\circ}C\; \;

 

 

 

 

 

Option 2)

75^{\circ}C\; \;

Option 3)

60^{\circ}C\; \;

Option 4)

35^{\circ}C\; \;

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