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# I need help with The bob of a simple pendulum of mass m and total energy E will have maximum linear momentum equal to

The bob of a simple pendulum of mass m and total energy E will have maximum linear momentum equal to

• Option 1)

$\sqrt{{\frac{2E}{m}}}$

• Option 2)

$\sqrt{2mE}$

• Option 3)

2mE

• Option 4)

mE2

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As we have learnt,

Simple Pendulum -

$\dpi{100} T=2\pi \sqrt{\frac{l}{g}}$

$\dpi{100} l\rightarrow length\, of\, pendulum$

$\dpi{100} g\rightarrow acc^{n}\, due\, to\, gravity$.

- wherein

$E =\frac{P^2}{2m}$

where E = Kinetic Energy, P = Momentum, m = Mass

So, $P = \sqrt{2mE}$

Option 1)

$\sqrt{{\frac{2E}{m}}}$

Option 2)

$\sqrt{2mE}$

Option 3)

2mE

Option 4)

mE2

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