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  • If a coil has 1 turn and 1 amp of current is flowing in a circuit , then coefficient of self induction would be , Where <img alt="\phi" src="http://entrancecorner.oncodecogs.com/gif.latex?%5Cp

If a coil has 1 turn and 1 amp of current is flowing in a circuit , then coefficient of self induction would be , Where \phi  is flux 

Option: 1

\phi


Option: 2

\phi/2


Option: 3

\phi/4


Option: 4

\phi/6 


Answers (1)

best_answer

As we have learned

Co efficient of self induction -

\phi \, \alpha \, I\Rightarrow N\phi \, \alpha\: I

N\phi \,=L\, I

L=\frac{N\phi }{I}\,
 

- wherein

N\phi = Number of flux linkage with coil.

 

 Number of flux linkage with coil is directly proportional to current i 

N \phi \propto i

N \phi = L i

L = N \phi /i

L = \phi  

L is coefficient of self induction 

 

 

 

 

 

 

 

Posted by

SANGALDEEP SINGH

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