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If A,B are square matrices,then ABB'A is

Option: 1

Symmetric


Option: 2

Data insufficient


Option: 3

Skew-Symmetric


Option: 4

None


Answers (1)

best_answer

As we learnt

 

Property of Transpose -

\left ( \alpha A \right ){}'= \alpha A{}'

(AB)^{'} =B^{'}A^{'}

- wherein

\alpha being scalar ; A{}' is transpose of A

 

 

 \left ( ABB'A \right )'=(B'A')'(AB)'

                      =\left ( AB \right )\left ( B'A' \right )= ABB'A'

So the given matrix is symmetric.

 

Posted by

Rakesh

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