If C = 0.000521 mol L^{-1}and \Lambda_m = 147.81 Scm^2mol^{-1}, then what would be the value of \Lambda^o_m if A = 87.46 \frac{S cm^2 mol^{-1}}{(mol L^{-1})^\frac{1}{2}}

 

Answers (1)

We know,

Variation of Molar Conductivity in strong electrolyte is:

\Lambda _m=\Lambda^{0}_ m-AC^{\frac{1}{2}}

(For strong electrolyte, \Lambda m increases slowly with dilution.)

Putting the values of A and C

 \\ \Lambda_m = \Lambda_m^o - AC^{\frac{1}{2}} \\*\Rightarrow \Lambda^o_m = \Lambda_m + AC^{\frac{1}{2}} = 147.81 + 87.46\times 0.000521 \\= 147.8555 \approx 147.856

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