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If \Delta Q heat is given to a substance changes its state at constant temprature T then change in entropy ds will be 

Option: 1

\pm \frac{mL}{T}


Option: 2

\pm \frac{mC}{T}


Option: 3

\pm mL


Option: 4

\pm mC


Answers (1)

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As we have learned

Entropy for solid and liquid -

When heat is given to a substance to change its state at constant temperature.

- wherein

\Delta S= \frac{mL}{T}

L= Latent \, Heat

T in kelvin

 

 \frac{d\theta }{dT} = \pm \frac{mL}{T}  

When substance changes its state at constant temprature d \theta = \pm mL  

where (+ve) signe refers to heat absorption and (-ve ) sign to heat evolution 

Posted by

SANGALDEEP SINGH

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