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If the de Broglie wavelength of the electron in n th Bohr orbit in a hydrogenic atom is equal to 1.5 \pi a_{0} (a0 is Bohr radius), then the value of n/z is :

 

Answers (1)

As we have learned in debroglics wavelength

we know

2\pi r =n\lambda

2\pi\: a_{0}\: \frac{n^{2}}{z}=n\lambda

2\pi\: a_{0}\: \frac{n^{2}}{z}=n \times 1.5 \pi a_{0}

\frac{n}{z}=\frac{1.5}{2}=\frac{3}{4}

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lovekush

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