If the de Broglie wavelength of the electron in n th Bohr orbit in a hydrogenic atom is equal to 1.5 \pi a_{0} (a0 is Bohr radius), then the value of n/z is :

 

Answers (1)

As we have learned in debroglics wavelength

we know

2\pi r =n\lambda

2\pi\: a_{0}\: \frac{n^{2}}{z}=n\lambda

2\pi\: a_{0}\: \frac{n^{2}}{z}=n \times 1.5 \pi a_{0}

\frac{n}{z}=\frac{1.5}{2}=\frac{3}{4}

Preparation Products

JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Knockout JEE Main April 2021 (Subscription)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 6999/- ₹ 5/-
Buy Now
Knockout BITSAT 2020

It is an exhaustive preparation module made exclusively for cracking BITSAT..

₹ 4999/- ₹ 1999/-
Buy Now
Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Exams
Articles
Questions